C^2-5C+2=-2

Solution for C^2-5C+2=-2 equation:

Simplifying
C2 + -5C + 2 = -2

Reorder the terms:
2 + -5C + C2 = -2

Solving
2 + -5C + C2 = -2

Solving for variable 'C'.

Reorder the terms:
2 + 2 + -5C + C2 = -2 + 2

Combine like terms: 2 + 2 = 4
4 + -5C + C2 = -2 + 2

Combine like terms: -2 + 2 = 0
4 + -5C + C2 = 0

Factor a trinomial.
(1 + -1C)(4 + -1C) = 0

Subproblem 1
Set the factor '(1 + -1C)' equal to zero and attempt to solve:

Simplifying
1 + -1C = 0

Solving
1 + -1C = 0

Move all terms containing C to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1C = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1C = 0 + -1
-1C = 0 + -1

Combine like terms: 0 + -1 = -1
-1C = -1

Divide each side by '-1'.
C = 1

Simplifying
C = 1
Subproblem 2
Set the factor '(4 + -1C)' equal to zero and attempt to solve:

Simplifying
4 + -1C = 0

Solving
4 + -1C = 0

Move all terms containing C to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1C = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1C = 0 + -4
-1C = 0 + -4

Combine like terms: 0 + -4 = -4
-1C = -4

Divide each side by '-1'.
C = 4

Simplifying
C = 4
Solution
C = {1, 4}